![]() ![]() KCL says the sum of the incoming currents and outgoing current at a node is equal to 0, giving youBecause you have the same voltage v(t) across each of the parallel inductors, you can rewrite the equation asThis equation shows how you can reduce the parallel inductors to one single inductor. ![]() Take a look at the circuit with three series inductors shown in the top diagram.Because the inductors are connected in series, they have the same currents:i 1(t) = i 2(t) =i 3(t) = i(t)Add up the voltages from the series inductors to get the net voltage v(t), as follows:For a series inductors, you have an equivalent inductance ofL EQ = L 1 + L 2 + L 3For a parallel connection of inductors, apply Kirchhoff’s current law (KCL) in the bottom diagram of the figure. ![]() I need the open loop transfer function of this, and it should be similar to the one I plotted on MATLAB using the transfer function I. Input voltage 400 V, Output voltage 200 V, Output power 100 W, L 100 uH, C 4.4 uH, switching frequency 300 kHz. Calculate total inductance for series and parallel inductorsInductors connected in series or connected in parallel can be reduced to one single inductor. I have a synchronous buck converter with the following specs:. The inductor absorbs power from a circuit when storing energy, and the inductor releases the stored energy when delivering energy to the circuit.To visualize the current and energy relationship shown here, which shows the current as a function of time and the energy stored in an inductor.This also shows how you can get the current from the inductor relationship between current and voltage. ![]()
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